Hi, can you help me to find the Nearest tenth.And measure of acute angle that the given lineforms with a horizontal line, please!

Step 1:
Write the equation of the line in the form of y = mx + c
m = slope
Step 2
[tex]\begin{gathered} \text{Slope = tan}\theta \\ \text{m = tan}\theta \end{gathered}[/tex]Step 3
From the equation
[tex]\begin{gathered} \text{y = }\frac{1}{2}x\text{ + 4} \\ m\text{ = }\frac{1}{2} \end{gathered}[/tex]Step 4:
[tex]\begin{gathered} m\text{ = tan}\theta \\ \frac{1}{2}\text{ = tan}\theta \\ \theta=tan^{-1}(\frac{1}{2}) \\ \theta\text{ = 26.6} \end{gathered}[/tex]Final answer
The measure of acute angle = 26.6