Given:
The right triangle with bisector length 3120 and hypotenuse length 6400+x.
Required:
Find the x.
Explanation:
We will redraw figure first
First we will apply Pythagoras theorem on triangle ADB
[tex]\begin{gathered} Base^2+perpendicular^2=hypotenuse^2 \\ 3120^2+6400^2=AB^2 \\ AB=7120 \end{gathered}[/tex]
Now, we will apply on BDC
[tex]3120^2+x^2=BC^2[/tex]
Now, in triangle ABC
[tex]\begin{gathered} 7120^2+x^2+3120^2=(6400+x)^2 \\ 7120^2+x^2+3120^2=6400^2+x^2+2\times6400\times x \\ 7120^2+3120^2=6400^2+12800x \\ x=1521 \end{gathered}[/tex]
Answer:
The value of x is 1521.
