How much of the initial mass remains after 80 years? (Round your answer to three decimal places.)

Given
[tex]y=11(\frac{1}{2})^{\frac{t}{30}}[/tex]When t = 80
We substitute for t
[tex]y=11(\frac{1}{2})\frac{}{}^{\frac{80}{30}}[/tex]Simplify
[tex]y=11(\frac{1}{2})^{\frac{8}{3}}[/tex]Simplify further
[tex]y=1.732g[/tex]The final answer