We are given the expression;
[tex]12+30y[/tex]To factor a given expression, we take each part separately and look for any factors that can divide both without remainders.
Looking at the first one;
[tex]12=2\times2\times3[/tex]And then the other one;
[tex]30y=2\times3\times5\times y[/tex]Notice that 2 and 3 afre common factors (that is 2 times 3 = 6).
Hence, we can factor out 6 from both parts of this expression as follows;
[tex]\frac{12}{6}+\frac{30y}{6}[/tex]Or if you want it to look more simplified (for the sake of understanding the steps better);
[tex]\begin{gathered} \frac{(2\times2\times3)}{2\times3}+\frac{(2\times3\times5\times y)}{2\times3} \\ =2+(5\times y) \\ =2+5y \end{gathered}[/tex]This means we can now re-write after factoring out 6;
[tex]6(2+5y)[/tex]That is;
[tex]12+30y=6(2+5y)[/tex]ANSWER:
[tex]6(2+5y)[/tex]