ANSWER:
0.4375 m
STEP-BY-STEP EXPLANATION:
Given:
Masses and positions of 3 objects are:
m1 = 1 kg located x1 = 0 m
m2 = 1.5 kg located x2 = 0.5 m
m3= 1.1kg located x3 = 0.5 + 0.25 = 0.75 m
Therefore, the center of mass of system is:
[tex]\begin{gathered} x_{cm}=\frac{m_1\cdot x_1+m_2\cdot x_2+m_3\cdot x_3}{m_1+m_2+m_3} \\ \\ \text{ We replacing:} \\ \\ x_{cm}=\frac{1\cdot0+1.5\cdot0.5+1.1\cdot0.75}{1+1.5+1.1} \\ \\ x_{cm}=\frac{1.575}{3.6} \\ \\ x_{cm}=0.4375\text{ m} \end{gathered}[/tex]
Therefore, the center of mass is 0.4375 meters from the left.
