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Moments after making the dreaded decision to jump out the door of the airplane, a skydiver's 89.5-kg body experiences 130 N of air resistance. The magnitude of the skydiver's downward acceleration at this instant in time is ______ m/s^2. Use the approximation g ≈ 10 m/s^2.

Respuesta :

Given:

The mass of the skydiver is,

[tex]m=89.5\text{ kg}[/tex]

The air resistance is,

[tex]R=130\text{ N}[/tex]

To find:

The downward acceleration of the skydiver

Explanation:

The resultant downward force is,

[tex]\begin{gathered} F_{net}=mg-R \\ =89.5\times10-130 \\ =765\text{ N} \end{gathered}[/tex]

The downward acceleration is,

[tex]\begin{gathered} a=\frac{F_{net}}{m} \\ =\frac{765}{89.5} \\ =8.55\text{ m/s}^2 \end{gathered}[/tex]

Hence, the downward acceleration is,

[tex]8.55\text{ m/s}^2[/tex]

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