19. Two charges (Q1=-1.7x10°C and Q2= 4.4x10-6C) are separated by 0.03m. What isthe electric force between them?I

Apply Coulomb's Law:
[tex]Fc=\frac{kq1q2}{r^{^2}}[/tex]Where:
F = Electric Force [N]
k = Coulomb constant = 9 x 10 ^9 Nm^2 / C^2
q1 = charge 1 = -1.7x10^-9^ C
q2= charge 2 = 4.4x10^^-6
r = distance = 0.03 m
Replacing:
[tex]Fc=\frac{(9x10^9)(-1.7x10^{-9})(4.4x10^{-6})}{(0.03)^2}[/tex]Fc = -0.0748 N
C