Given data:
The coordinate of point A is (6, 1).
The coordinate of point B is (-2, 5).
The coordinate of C is (0, 2).
The mid point of AB is,
[tex]\begin{gathered} x=\frac{6-2}{2} \\ =2 \\ y=\frac{1+5}{2} \\ =3 \end{gathered}[/tex]
The coordinate of mid point is M(2, 3).
The distance CM is,
[tex]\begin{gathered} d=\sqrt[]{(0-2)^2+(2-3)^2} \\ =\sqrt[]{4+1} \\ =\sqrt[]{5} \end{gathered}[/tex]
Thus, the distance is (5)^(1/2).
