We will have the following:
[tex]N=Noe^{kt}[/tex][tex]50=100e^{710k}\Rightarrow0.5=e^{710k}\Rightarrow\ln (0.5)=710k\Rightarrow k=\frac{\ln(0.5)}{710}[/tex]From this we have that the equation is:
[tex]N=100e^{(\frac{\ln(0.5)}{710})t}[/tex]Now, we replace the time:
[tex]N=100e^{(\frac{\ln(0.5}{710})(300)}\Rightarrow N\approx74.6[/tex]So, there will be approximately 74.6 grams of silicon-32.
