[tex]\begin{gathered} -(x-2)^2-4=-(x^2-4x+4)-4=-x^2+4x-8 \\ \text{vertex in x} \\ x=-\frac{4}{-2}=2 \\ \text{vertex in y} \\ y=-4+8-8=-4 \\ (2,-4) \\ \text{axis of symmetry } \\ x=2 \\ \text{max at x=2} \\ \text{Domain All real numbers} \\ \text{range (-}\infty,-4\rbrack \\ It\text{ opens downwards} \end{gathered}[/tex]
