An initially stationary body explodes, at which point it splits into three smaller bodies A, B and C. Bodies A and B acquire equal momentum p A = p B = 10Kg * m / s that have vertical directions between them. The measure of momentum that body C acquires immediately after the explosion is a. 10 Kg * m / s b. 20 Kg * m / s c. 10 roots 2 Kg * m / s Choose the correct answer and justify your choice.

Respuesta :

Given data

*The momentum of the given body (A) is

[tex]p_A=10\text{ kg.m/s}[/tex]

*The momentum of the given body (B) is

[tex]p_B=\frac{10\operatorname{kg}.m}{s}_{}[/tex]

The formula for the momentum of the body (C) acquires immediately after the explosion is given as

[tex]p_C=\sqrt[]{p^2_A+p^2_B}[/tex]

Substitute the known values in the above expression as

[tex]\begin{gathered} p_C=\sqrt[]{(10)^2+(10)^2} \\ =\sqrt[]{200} \\ =10\sqrt[]{2}\text{ kg.m/s} \end{gathered}[/tex]

Hence, the correct option is (c)