CazC122508 CazC122508

28-10-2022
Mathematics

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What pressure would 0.150 moles of nitrogen gas have (given a temperature of 300 K and a volume of 8.90 L)?

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DamareonG553634 DamareonG553634

28-10-2022

PV = nRT

P = Pressure = ?

V=Volume = 8.90 L

n=number of moles = 0.150 mol

R=constant = 8314 L·Pa/K·mol)

T=Temperature = 300K

P*8.9 = 0.150*8314*300

P*8.9 = 37413

P = 37413/8.9

P=4203.7 Pa

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