The given function is:
[tex]g(x)=3-\frac{1}{4}x[/tex]
At x = 0:
[tex]\begin{gathered} g(0)=3-\frac{1}{4}(0) \\ g(0)=3-0 \\ g(0)=3 \end{gathered}[/tex]
Therefore, one point is (0, 3)
At x = 12:
[tex]\begin{gathered} g(12)=3-\frac{1}{4}(12) \\ \\ g(12)=3-3 \\ \\ g(12)=0 \end{gathered}[/tex]
Another point is (12, 0)
The graph of g(x) considering the points (0, 3) and (12, 0) is plotted below
