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if a dealer buys a car from the manufacturer for $21,050 and then sells it for $30,038, what is his markup? the markup is ____'% (type an integer or decimal rounded to the nearest tenth as needed)

Respuesta :

Given:

a.) A dealer buys a car from the manufacturer for $21,050.

b.) He sells it for $30,038.

Let's now determine his markup,

We get,

[tex]\text{ Mark up (\%) = }\frac{\text{ \$30,038 - \$21,050}}{\text{ \$21,050}}\text{ x 100}[/tex][tex]=\text{ }\frac{\text{ \$8,988}}{\text{ \$21,050}}\text{ x 100}[/tex][tex]=\text{ 0.42698337 x 100}[/tex][tex]\text{ }=\text{ 42.698337 \%}[/tex][tex]\text{ Mark up }\approx\text{ 42.70\%}[/tex]

Therefore, the mark up is 42.70%

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