ANSWER :
The answer is :
[tex]7^{5x+11}[/tex]
EXPLANATION :
Note that in dividing expressions with exponents and having the same bases, the exponents are subtracted from each other.
[tex]\frac{a^x}{a^y}=a^{x-y}[/tex]
From the problem, we have :
[tex]\begin{gathered} \frac{7^{5x+20}}{7^9}=7^{(5x+20)-9} \\ =7^{5x+11} \end{gathered}[/tex]
