In the circle below, if arc AB = 97 ° and arc CD = 29 °, find the measure of < BPA.

To solve that question we will use the fact that
[tex]\frac{AB-CD}{2}=\angle BPA[/tex]Then, using that formula we can find the angle we want, we know that
AB = 97°
CD = 29°
Then
[tex]\begin{gathered} \begin{equation*} \frac{AB-CD}{2}=\angle BPA \end{equation*} \\ \\ \angle BPA=\frac{97-29}{2} \\ \\ \operatorname{\angle}BPA=\frac{68}{2} \\ \\ \operatorname{\angle}BPA=34° \end{gathered}[/tex]The angle is 34°, and the correct answer is the letter B.