To solve the equation for "x" we first need to simplify it.
[tex]\begin{gathered} 2x\cdot(2x+1)=2\cdot(x+18)_{} \\ 4x^2+2x=2x+36 \\ 4x^2+2x-2x-36=0 \\ 4x^2-36=0 \\ 4x^2=36 \\ x^2=\frac{36}{4} \\ x^2=9 \\ \text{ We now apply the square roots method} \\ \sqrt[]{x^2}=\pm\sqrt[]{9} \\ x=\pm3 \end{gathered}[/tex]The answer for this equation is either -3 or 3.
