How tall is the tower?X60°17 ft-50 ft[ ? ] ftRound to the nearest tenth.

We can use the trigonometric tangent identity, this is:
[tex]\tan z=\frac{opposite\text{ side}}{\text{adjacent side}}[/tex]Where z = 60°
opposite side = x
adjacente side = 50ft
Then:
[tex]\begin{gathered} \tan 60=\frac{x}{50} \\ x=50\times\tan 60 \\ x=50\sqrt[]{3}=86.6 \end{gathered}[/tex]And the tower height is:
[tex]86.6+7=93.6[/tex]Answer: 93.6 ft