Answer:
the x-intercept is at;
[tex](8,0)[/tex]
the y-intercept is at;
[tex](0,-12)[/tex]
Explanation:
Given the equation;
[tex]3x-2y=24[/tex]
We want to find the x and y intercept of the equation;
Recall that the x-intercept is at y=0;
substituting y=0 into the equation;
[tex]\begin{gathered} 3x-2y=24 \\ 3x-2(0)=24 \\ 3x=24 \\ x=\frac{24}{3} \\ x=8 \end{gathered}[/tex]
So, the x-intercept is at;
[tex](8,0)[/tex]
Also, the y-intercept is at x=0;
substituting x=0 into the equation;
[tex]\begin{gathered} 3(0)-2y=24 \\ -2y=24 \\ y=\frac{24}{-2} \\ y=-12 \end{gathered}[/tex]
Therefore, the y-intercept is at;
[tex](0,-12)[/tex]
