Part A
[tex]R=(105-\frac{q}{90})^q[/tex][tex]R=105q-\frac{q^2}{90}[/tex][tex]\begin{gathered} Profit=R-C=105q-\frac{q^2}{90}-(22000+90q) \\ \\ p(q)=-\frac{q^2}{90}+15q-22000 \end{gathered}[/tex]Part B
[tex]\begin{gathered} P^{^{\prime}}=-\frac{q}{45}+15 \\ \\ \\ p^{^{\prime}}(1000)=-\frac{1000}{45}+15^2 \\ P^{^{\prime}}(1000)=-22.22222+225 \\ P^{^{\prime}}(1000)=202.777777778 \end{gathered}[/tex]The final answer
Part A
[tex]P(q)=-\frac{q^2}{90}+15q-22000[/tex]Part B
[tex]P^{^{\prime}}(1000)=202.777778[/tex]