Given:
The number of people are in the favor of restructuring is 50.
The number of people are in the oppose of restructuring is 82 .
The total number of persons is 182.
The probability of persons is in the favor of restructuring is,
[tex]\begin{gathered} \text{Probability}=\frac{Desired\text{ outcomes}}{t\text{otal outcomes}} \\ P_F=\frac{50}{182} \end{gathered}[/tex]The probability of persons is in the oppose of restructuring is,
[tex]P_O=\frac{82}{182}[/tex]To find the probability that a randomly selected person is either in favor of or opposed to the restructuring,
[tex]\begin{gathered} P(\text{Favor or oppose)=}P_F+P_O \\ =\frac{50}{182}+\frac{82}{182} \\ =\frac{50+82}{182} \\ =\frac{132}{182} \\ =\: \frac{66}{91} \end{gathered}[/tex]Answer:
[tex]P=\frac{66}{91}[/tex]