Y varies inversely as the square of x. This relationship can be expressed as
[tex]y=\frac{k}{x^2}[/tex]where k is a constant. we need to find the value of k
To do that, we use the provided data, y = 9 when x = 15. Substituting in the above equation:
[tex]9=\frac{k}{15^2}[/tex]Solving for k:
[tex]k=9\cdot15^2=2,025[/tex]The equation is, then:
[tex]y=\frac{2,025}{x^2}[/tex]We finally need to find the value of y when x = 2:
[tex]y=\frac{2,025}{2^2}=\frac{2,025}{4}=506.25[/tex]y is 506.26 when x = 2
