Given data
*The given height is h = 100 m
*The given density of the water is D_w = 1000 kg.m^3
*The value of the acceleration due to gravity is g = 9.8 m/s^2
The formula for the water pressure at the bottom of the tank is given as
[tex]P=D_wgh[/tex]Substitute the known values in the above expression as
[tex]\begin{gathered} P=(1000)(9.8)(100) \\ =9.8\times10^5\text{ Pa} \end{gathered}[/tex]Hence, the water pressure at the bottom of the tank is P = 9.8 × 10^5 Pa
