Given the following equation:
[tex]5x-2y=10[/tex]We can find the y-intercept and the slope if we write it in slope-intercept form. To do this, we have to solve for 'y'. We would get the following:
[tex]\begin{gathered} 5x-2y=10 \\ \Rightarrow-2y=10-5x \\ \Rightarrow y=\frac{10-5x}{-2}=\frac{10}{-2}-\frac{5x}{-2}=-5+\frac{5}{2}x \\ y=\frac{5}{2}x-5 \end{gathered}[/tex]therefore, we have that the slope is m = 5/2 and the y-intercept is -5
To find the x-intercept, we can make y = 0 and solve for x to get the following:
[tex]\begin{gathered} y=0 \\ \Rightarrow5x-2(0)=10 \\ \Rightarrow5x=10 \\ \Rightarrow x=\frac{10}{5}=2 \\ x=2 \end{gathered}[/tex]therefore, the x-intercept is 2
