Find the expected value of the winningsfrom a game that has the followingpayout probability distribution:Payout ($)| 012510Probability 0.12 0.2 0.38 0.2 0.1Expected Value = [?]Round to the nearest hundredth.

expected value is 2.96
it comes from the formula
[tex]E(x)\text{ = }\Sigma(x)(P(x))[/tex]E(x) is the expected value
x is the payout
p(x) is the probability