Respuesta :
Given:
The total investment = $12000
Let x denote the first investment anf y denote the second investment.
[tex]x+y=12000\ldots.\ldots(1)[/tex]Jessica lost 6% on the first investment and earned 7% on the other.
[tex]\begin{gathered} -6\text{ \%x+7\%y=476} \\ -\frac{6}{100}x+\frac{7}{100}y=476 \\ -0.06x+0.07y=476\ldots\text{.}(2) \end{gathered}[/tex]Solve the equations,
[tex]\begin{gathered} x+y=12000 \\ x=12000-y \\ \text{Put it in equation (2)} \\ -0.06(12000-y)+0.07y=476 \end{gathered}[/tex]Solving it further,
[tex]\begin{gathered} -0.06(12000-y)+0.07y=476 \\ -720+0.06y+0.07y=476 \\ 0.13y=1196 \\ y=9200 \end{gathered}[/tex]The value of x is,
[tex]\begin{gathered} x=12000-y \\ x=12000-9200 \\ x=2800 \end{gathered}[/tex]Answer:
The first investment is $2800.
The second investment is $9200.
