Given:
The mass of the ball is m = 0.05 kg
The speed of the ball is
[tex]v_f=75\text{ m/s}[/tex]
The initial speed of the ball is
[tex]v_i=\text{ 0 m/s}[/tex]The time duration is t = 0.01 s
Required: Impulse and average force
Explanation:
The impulse can be calculated as
[tex]\begin{gathered} Impulse\text{ = change in momentum} \\ =mv_f-mv_i \\ =(0.05\times75)-(0.05\times0) \\ =3.75\text{ N s} \end{gathered}[/tex]The average force can be calculated as
[tex]\begin{gathered} F_{av}=\frac{Impulse}{t} \\ =\frac{3.75}{0.01} \\ =\text{ 375 N} \end{gathered}[/tex]Final Answer: The impulse of the golf ball is 3.75 N.s
The average force is 375 N
