Respuesta :

[tex]\begin{gathered} y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1) \\ y-(-8)=\frac{5-(-8)}{8-4}(x-4) \\ y+8=\frac{13}{4}(x-4) \\ 4(y+8)=\frac{13}{4}(x-4)\times4 \\ 4(y+8)=13(x-4) \\ 4y+32=13x-52 \\ 13x-4y=84 \end{gathered}[/tex]

thats the equation

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