From the given sequence ,we can note that the common difference between consecutive numbers is 9. Thats because
[tex]\begin{gathered} 4-(-5)=9 \\ 13-4=9 \\ 22-13=9 \\ 31-22=9 \end{gathered}[/tex]
This means that
[tex]f(n)-f(n-1)=9[/tex]
or equivalently,
[tex]f(n)=f(n-1)+9\text{ for n}\ge2[/tex]
We can also obtain the same result by taking into account the common difference and the fact that the first number in the sequence is -5. So we can write
[tex]f(n)=9n-5[/tex]
For instance,
[tex]\begin{gathered} n=0\Rightarrow f(0)=-5 \\ n=1\Rightarrow f(1)=9-5=4 \\ n=2\Rightarrow f(2)=18-5=13 \\ n=3=f(3)=27-5=22 \\ n=4\Rightarrow f(4)=36-5=31 \end{gathered}[/tex]
Therefore, the functions that define the given sequence are:
[tex]\begin{gathered} f(1)=-5,\text{ f\lparen n\rparen=f\lparen n-1\rparen+9 for n}\ge2 \\ and \\ f(n)=9n-5 \end{gathered}[/tex]
which correspond to options 2 and 5 from top to bottom.