[tex]L_{major\text{ arc}}=\frac{\theta}{360}\times2\pi r[/tex][tex]\text{Where r=16ft and }\theta=\frac{3\pi}{2}[/tex][tex]\begin{gathered} L_{major\text{ arc}}=\frac{3\pi}{2\times360}\times2\pi\times16 \\ L_{major\text{ arc}}=\frac{4}{15}\pi^2 \end{gathered}[/tex][tex]\begin{gathered} \text{The arc subtended by the minor arc is} \\ 2\pi-\frac{3\pi}{2}=\frac{\pi}{2} \end{gathered}[/tex][tex]\begin{gathered} L_{\min or\text{ arc}}=\frac{\pi}{2\times360}\times2\pi\times16 \\ L_{\min or\text{ arc}}=\frac{2}{45}\pi^2 \end{gathered}[/tex]
