1)
the area of the given figure is,
base x height = 9.5 x 14 = 133
2)
the area of the given figure is ,
[tex]=\frac{1}{2}(30+19)\times16[/tex][tex]\begin{gathered} =\frac{1}{2}\times49\times16 \\ =392 \end{gathered}[/tex]
thus, the area is 392
3)
the area of the half circle is,
diameter d = 11
[tex]=\frac{1}{2}\times\pi\times\frac{d^2}{4}[/tex][tex]=\frac{1}{2}\times\frac{22}{7}\times\frac{11^2}{4}[/tex][tex]\begin{gathered} =\frac{11^3}{28} \\ =\frac{133}{28} \\ =47.52 \end{gathered}[/tex]
4)
the area of the trinagle is
1/2 x base x height
= 1/2 x 26.4 x 11
= 13.2 x 11
= 145.2
