Given:
Triangle QRS is drawn with vertices at Q(−2, −2), R(−6, −6), S(−5, −1). After a rotation, image Q′R′S′ has vertices Q′(2, −2), R′(6, −6), S′(1, −5).
The graph of the given triangles will be as shown in the following figure:
From the figure, we can conclude the given rotation as follows:
[tex](x,y)\to(-y,x)[/tex]Which represents the rotation of 90° counter-clockwise
We will find the following:
Part A: Determine the two different rotations that would create the image.
The same rule can be obtained using the rotation of 270° clockwise.
Part B: Explain how you know your answer to Part A is correct.
As shown in the figure, if we apply the second method, we will get the same image of the triangle as the two methods have the same rule.
