Respuesta :

General form of the equation of a circle:

[tex](x-h)^2+(y-k)^2=r^2[/tex]

The coordinates of the center are (h,k)

The radius is r.

For the given circle:

Coordinates of the center: (-2,4)

radius: 6

Equation:

[tex]\begin{gathered} (x-(-2))^2+(y-4)^2=6^2 \\ \\ (x-(-2))^2+(y-4)^2=36 \end{gathered}[/tex]