How do I solve this? What does it mean by satisfying this equation?

Given:
[tex]\begin{gathered} sin\theta=\frac{1}{\sqrt{2}} \\ \theta=\frac{\pi}{4} \end{gathered}[/tex]Find: the another equivalent value of
[tex]\theta[/tex]Explanation:
[tex]\begin{gathered} sin\frac{\pi}{4}=\frac{1}{\sqrt{2}} \\ sin(\pi-\frac{\pi}{4})=\frac{1}{\sqrt{2}} \\ sin\frac{4\pi-\pi}{4}=\frac{1}{\sqrt{2}} \\ sin\frac{3\pi}{4}=\frac{1}{\sqrt{2}} \end{gathered}[/tex]Final answer: The required answer is
[tex]\frac{3\pi}{4}[/tex]