we have the equation
[tex]\frac{4}{5}+\frac{3}{x}=\frac{1}{2}[/tex]Remember that the value of x cannot be equal to zero, because the denominator cannot be equal to zero
Simplify the expression
Multiply both sides by 10x
[tex]\frac{4}{5}\cdot10x+\frac{3}{x}\cdot10x=\frac{1}{2}\cdot10x[/tex]simplify
[tex]\begin{gathered} 8x+30=5x \\ 8x-5x=-30 \\ 3x=-30 \\ x=-10 \end{gathered}[/tex]therefore
The equation is solvable
