The given system of equations is expressed as
2x + y = 4
y = 3x - 1
We would apply the method of substitution by substituting equation 2 into equation 1. It becomes
2x + 3x - 1 = 4
5x - 1 = 4
5x = 4 + 1
5x = 5
x = 5/5
x = 1
Substituting x = 1 into the second equation, it becomes
y = 3 * 1 - 1
y = 3 - 1
y = 2
Therefore, (1, 2) is a solution to both equations
