To find these values, we just need to substitute the values of x for the corresponding value and evaluate:
[tex]\begin{gathered} h\mleft(x\mright)=x^2-3x+5 \\ h\mleft(-3\mright)=\left(-3\right)^2-3\left(-3\right)+5=9+9+5=23 \end{gathered}[/tex][tex]\begin{gathered} h\mleft(x\mright)=x^2-3x+5 \\ h\mleft(5\mright)=5^2-3\left(5\right)+5=25-15+5=15 \end{gathered}[/tex]