which has more kinetic energy, a 0.0020-kg bullet traveling at 400 m /s or a ( 6.4×10^7)-kg ocean liner traveling at 10 m/s ( 20 knots) Justify your answer.

Respuesta :

First, we will need to know the formula to calculate the kinetic energy

[tex]K.E.=\frac{1}{2}\cdot m\cdot v^2[/tex]

where m is the mass and v is the speed

then we will calculate the kinetic energy for each case

For the bullet

m=0.0020 kg

v=400 m/s

[tex]K.E.=\frac{1}{2}(0.0020)\cdot(400)^2=160J[/tex]

for the ocean liner

m=6.4x10^7 kg

v=10 m/s

[tex]K.E.=\frac{1}{2}(6.4\times10^7)\cdot(10)^2=3200000000J=32\times10^8J[/tex]

as we can see the ocean liner has more Kinetic energy.