We have two triangles. One is the dilated image, with a scale factor of 3, of the other triangle.
The angles of the dilated triangles stay the same, that is, they have the same measure.
The sides increase their length by a factor of 3.
Then, if we calculate the area, we will have:
[tex]A_2=\frac{b_2h_2}{2}=\frac{(3b_1)(3h_1)}{2}=9\frac{b_1h_1}{2}=9A_1[/tex]
Then, the area of the dilated triangle is 3^2=9 times the are of the pre-image triangle.
Answer: 1) The area of the image is nine times the area of the original triangle.