Given:
An aeroplane is flying towards the east in still air at 92 m/s.
The wind blows at 24 m/s towards the north.
To find: The vector diagram to find the resultant velocity of the aeroplane.
Explanation:
The vector diagram is shown below:
Each box is equal to 2 cm = 20 m/s
R is the resultant vector.
The magnitude of the resultant is
[tex]\begin{gathered} R=\sqrt[]{(24)^2+(92)^2} \\ =95.08\text{ m/s} \end{gathered}[/tex]The angle of the resultant that makes with the horizontal is
[tex]\begin{gathered} \theta=\tan ^{-1}(\frac{24}{92}) \\ =14.6^{\circ} \end{gathered}[/tex]
