Dilate the figure by the scale factor. Then enterthe new coordinates.A(1,4)K = 6C(-2,1)A' ([?], [])B' ([], [])C' ([], [])B(2,2)

We have a triangle and we have to dilate it with a facto of K.
As nothing else is specified, we will assume that the center of dilation is (0,0).
The rule for a dilation with factor k with center of dilation at the origin (0,0) can be written as:
[tex](x,y)\to(kx,ky)[/tex]We can draw the new triangle by applying this rule to the three vertices:
[tex]\begin{gathered} A=(1,4)\to A^{\prime}=(6*1,6*4)=(6,24) \\ B=(2,2)\to B^{\prime}=(6*2,6*2)=(12,12) \\ C=(-2,1)\to C^{\prime}=(6*(-2),6*1)=(-12,6) \end{gathered}[/tex]We can graph them as: