In a valid probability distribution, each probability must be between 0 and 1,inclusive, and the probabilities must add up to 1. If a probability distribution5has probabilities1,112, and x, what is the value of X?

In a valid probability distribution each probability must be between 0 and 1inclusive and the probabilities must add up to 1 If a probability distribution5has p class=

Respuesta :

Given:

The probability distribution is given by,

[tex]\frac{5}{12},\frac{1}{6},\frac{1}{3},x[/tex]

To find:

The value of x.

Explanation:

We know that,

The probabilities must add up to 1.

So, we write

[tex]\frac{5}{12}+\frac{1}{6}+\frac{1}{3}+x=1[/tex]

Solving for x we get

[tex]\begin{gathered} x=1-\frac{5}{12}-\frac{1}{6}-\frac{1}{3} \\ x=\frac{12-5-2-4}{12} \\ x=\frac{1}{12} \end{gathered}[/tex]

Therefore, the value of x is,

[tex]\frac{1}{12}[/tex]

Final answer: Option D

The value of x is,

[tex]\frac{1}{12}[/tex]