Given,
PD = 3, DB = 5, and PC = 2
Required
The value of segment CA.
By the definition of secant of the circle.
[tex]\begin{gathered} (AC+CP)\times CP=(BD+DP)\times DP \\ (AC+2)\times2=(5+3)\times3 \\ (AC+2)=8\times\frac{3}{2} \\ AC=4\times3-2 \\ AC=10 \end{gathered}[/tex]
Hence, the measure of segment AC is 10.
