Answer:
a) 4x to x is 75% decrease
b)0.25m
We want to find the percentage increase or decrease of each of the following;
Applying the formula;
[tex]\begin{gathered} \text{ \% change =}\frac{final\text{ value - initial value}}{\text{ initial value}}\times100\text{\%} \\ \text{if change is positive, then it increases.} \\ \text{if change is negative, it decreases} \end{gathered}[/tex]
a) 4x to x
[tex]\begin{gathered} \text{ \%P =}\frac{x-4x}{4x}\times100\text{\%}=-\frac{3x}{4x}\times100\text{\%} \\ \text{\%P =}-0.75\times100\text{\%} \\ \text{\%P =}-75\text{\%} \\ \therefore \\ 4x\text{ to }x\text{ }\Rightarrow75\text{\% decrease} \end{gathered}[/tex]
b) 0.25m to 0.5m
[tex]\begin{gathered} \text{ \%P =}\frac{0.5m-0.25m}{0.25m}\times100\text{\%}=\frac{0.25m}{0.25m}\times100\text{\%} \\ \text{ \%P =}1\times100\text{\%} \\ \text{ \%P =}100\text{\%} \\ \therefore \\ 0.25m\text{ to 0.5m }\Rightarrow\text{ 100\% increase} \end{gathered}[/tex]
