Triangle Proportionality and Angle Bisector TheoremsNeed answers and help please

Step 1:
Triangle PRS is similar QRS.
PR is similar to RQ
PS is similar to QS
Step 2:
PR = 14 - x
RQ = x
PS = 6
QS = 4
Step 3:
[tex]\begin{gathered} \frac{PR}{QR}\text{ = }\frac{PS}{QS} \\ \frac{14\text{ - x}}{x}\text{ = }\frac{6}{4} \\ \frac{14\text{ - x}}{x}\text{ = }\frac{3}{2} \\ 2(14\text{ - x) = 3x} \\ 28\text{ - 2x = 3x} \\ 28\text{ = 3x + 2x} \\ 28\text{ = 5x} \\ x\text{ = }\frac{28}{5} \\ x\text{ = 5.6} \end{gathered}[/tex]