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A concave lens creates a virtualimage at -47.0 cm with amagnification of +1.75. What isthe object distance?(Mind your minus signs.)(Unit = cm)

Respuesta :

Answer:

Object distance = 26.86 cm

Explanation:

Given:

Image distance, v = -47.0 cm

Magnification, M = 1.75

Object distance, u = ?

[tex]\begin{gathered} M=\frac{|v|}{|u|} \\ \\ 1.75=\frac{47.0}{u} \\ \\ u=\frac{47.0}{1.75} \\ \\ u=26.86\text{ cm} \\ \end{gathered}[/tex]

Object distance = 26.86 cm

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