The circle below is centered at (10,4) and has a radius of 4. What is itsequation?101010O A. (x - 10)2 + (y - 4)2 = 16O B. (x-4)2 + (-10)2 = 4O C. (x-4)2 + (-10)2 = 16OD. (x-10)2 + (x-4)2 = 4

The general equation of a circle with centre (h,k) and radius r is given as
[tex]\begin{gathered} (x-h)^2+(y-k)^2=r^2 \\ \text{where,} \\ (h,k)=(10,4) \\ r=4 \end{gathered}[/tex]By substitution, we will have,
[tex]\begin{gathered} (x-10)^2+(y-4)^2=4^2 \\ =(x-10)^2+(y-4)^2=16 \end{gathered}[/tex]Hence,
The correct answer is OPTION A