Given:
Radius = 3
Center = (8,5)
Find-: Use the Pythagorean theorem in the "x" and "y" terms.
Sol:
Pythagorean theorem :
[tex]\text{ Hypotenuse}^2=\text{ Base}^2+\text{ Perpendicular}^2[/tex]
So,
a = x - 8
b = y - 5
[tex]\begin{gathered} a^2+b^2=r^2 \\ \\ (x-8)^2+(y-5)^2=(3)^2 \end{gathered}[/tex]
