Respuesta :

The commonly form of sine function used is the following:

[tex]y=A\sin (\frac{2\pi}{B}(x+C))+D[/tex]

Where:

- A is the amplitute

- B is the period

- C is the phase shift

- D is the vertical shift, or vertical translation.

For the cosine, we only change the sin to cos.

a) We have a sine function with amplitute 4 and period 3π. It is implied that there is no vertical trnslation and no phase shift, so they are 0.

Thus:

A = 4

B = 3π

C = 0

D = 0

[tex]\begin{gathered} y=4\sin (\frac{2\pi}{3\pi}(x+0))+0 \\ y=4\sin (\frac{2}{3}x) \end{gathered}[/tex]

b) We have a sine function, amplitude 3, period 2π, vertical translation -4 and phase shift π.

Thus:

A = 3

B = 2π

C = -4

D = π

[tex]\begin{gathered} y=3\sin (\frac{2\pi}{2\pi}(x+\pi))-4 \\ y=3\sin (x+\pi)-4 \end{gathered}[/tex]

c) We have a cosine function, amplitude 5, period π, vertical translation 1 and phase shift -π/2.

Thus:

A = 5

B = π

C = 1

D = -π/2

[tex]\begin{gathered} y=5\cos (\frac{2\pi}{\pi}(x-\frac{\pi}{2}))+1 \\ y=5\cos (2x-\pi)+1 \end{gathered}[/tex]