Explanation
a small charge q= 7.0 mC is found in a uniform E-fie E=3.2 N/C, determine the force on the charge
to solve this we need to use the expression:
[tex]\begin{gathered} F=qE \\ \text{where F is the force} \\ q\text{ is the charge} \\ E\text{ is the electric field} \end{gathered}[/tex]so
Let
[tex]\begin{gathered} q=7.0\text{ mC} \\ E=3.2\text{ N/C} \end{gathered}[/tex]replace
[tex]\begin{gathered} F=qE \\ F=7.0mC\cdot\text{ 3.2 N/C} \\ F=22.4\text{ Newtons} \end{gathered}[/tex]so, the force is 22.4 Newtons
I hope this helps you
